Re-arranging a formula to find Vm

  • Thread starter Thread starter Sparkyian
  • Start date Start date
  • Tags Tags
    Formula
AI Thread Summary
To rearrange the formula V(L) = V(m) - (V(m)/2fCR) to find V(m), start by multiplying both sides by 2fCR to eliminate the fraction. Next, isolate V(m) by moving all terms involving V(m) to one side of the equation and the constants to the other side. Continue simplifying and combining like terms until you arrive at the final form of V(m). The process primarily involves basic algebraic manipulation. Following these steps will yield the desired expression for V(m).
Sparkyian
Messages
9
Reaction score
0
Can anyone explain to me how to re-arrange the following formula to find V(m).

V(L)=V(m)-(V(m)/2fCR).

Please explain step by step as I am really stuck.

Thank you.
 
Physics news on Phys.org
It's just algebra. Start by multiplying both sides by 2fCR in order to get rid of the fraction. Then isolate Vm by putting all of the terms with Vm on one side, and all of the terms without Vm on the other side. Continue collecting terms and stuff until you're left with something of the form

Vm = blah.
 
Thank you.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top