Reactions of Halogens with Metals

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The discussion focuses on the oxidation of copper metal by bromine (Br2) and iodine (I2) in different solvents. The reactions are represented by the equations where copper reacts with bromine in aqueous solution and iodine in methanol. The net ionic equation for the reaction with Br2 is questioned, with a proposed equation suggesting the formation of copper(I) bromide (CuBr) as a solid. There is uncertainty about the formation of copper(I) iodide (CuI) in the reaction with I2, with concerns raised about whether a solid precipitate forms. The possibility of different copper halides, such as CuBr versus CuBr2, is also discussed, with lab notes indicating that Br2 is reduced to bromide ions (Br-). The main inquiry revolves around the expected color change and the physical state of the products formed in these reactions.
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To test the ability of Br2 and I2 to oxidize copper metal, the reactions take place between Br2water and I2 solution with copper:

Cu (s) + Br2 (aq) -> Cu2+ (aq) + 2Br- (Aq)

Cu(s) + I2 (methanol) -> Cu2+ (methanol) + 2I- (methanol).

Write the net ionic equations describing the results of these two experiments.

I believe that the Cu (s) should oxidize, and thus color change. Particularly with Br2 water (bromide water), so I recorded the net ionic equation as 2Cu (s) + Br2 (aq) -> 2CuBr(s)

However, I'm unsure if this is correct or what to do with the second equation.

Has anyone ever done these reactions or know them off hand? Is it possible that a precipiate could form between Cu2+ and I2?
 
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Why not CuI?

Actually I am sure about CuI, but I am not convinced you will get CuBr and not CuBr2.
 
Borek said:
Why not CuI?

Actually I am sure about CuI, but I am not convinced you will get CuBr and not CuBr2.

Well, CuI would have to be a solid. And I'm not convinced a solid was formed in this case. I suppose my main question is if the reaction between Cu and I2 results in a color change to Cu, would the product be a solid? CuI would have to be a solid to be written as such in the net ionic equation.

The lab notes predict Br2 reduces to Br2-, hence my writing CuBr
 
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