Reading an Electrodynamic Ammeter with 6 A Range and 100 Divisions

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The discussion centers on determining the deflection of an electrodynamic ammeter with a 6 A range and 100 divisions when energized by two different current inputs. The first input has a frequency of 500 Hz, while the second has a frequency of 0.318 Hz, leading to confusion about their effects on the ammeter's reading. The natural frequency of oscillation for the ammeter is 5 Hz, which is crucial for understanding its response to the inputs. The user calculated a deflection of 25 but seeks clarification on the differences in readings due to the varying frequencies. The conversation emphasizes the need for a deeper understanding of the ammeter's mechanics to solve the problem effectively.
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Homework Statement


What will the pointer of electrodynamic ammeter show (its natural frequency of oscillation is 5 Hz), if its input is energized by current:
a) i (t) = 1.5 + 4 sin (3146 t)
b) i (t) = 1.5 + 4 sin (2 t)
Ammeter has a range of 6 A and the scale has 100 divisions.

Homework Equations


The Attempt at a Solution

[/B]
My solution is 25 but I don't understand the difference between a) (where the frequency is 500 Hz) and b) (0.318 Hz).
 
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sol59 said:

Homework Statement


What will the pointer of electrodynamic ammeter show (its natural frequency of oscillation is 5 Hz), if its input is energized by current:
a) i (t) = 1.5 + 4 sin (3146 t)
b) i (t) = 1.5 + 4 sin (2 t)
Ammeter has a range of 6 A and the scale has 100 divisions.

Homework Equations


The Attempt at a Solution

[/B]
My solution is 25 but I don't understand the difference between a) (where the frequency is 500 Hz) and b) (0.318 Hz).
Hi sol59.
smiley_sign_welcome.gif


Describe what you understand by an electrodynamic ammeter.

What do you understand is meant by a natural frequency of oscillation of 5 Hz in the context of this problem.

Until you show you have done some work by yourself, we are not able to help you further.
 
NascentOxygen said:
Hi sol59.
smiley_sign_welcome.gif


Describe what you understand by an electrodynamic ammeter.

What do you understand is meant by a natural frequency of oscillation of 5 Hz in the context of this problem.

Until you show you have done some work by yourself, we are not able to help you further.

Hi, thanks for the reply:) It's ammeter with electrodynamic measuring mechanism (with one movable coil and one fixed coil). The natural frequency is the frequency at which the measuring mechanism tends to oscillate before the current is led into its input. I calculated the deflection as: (1.5*100)/6 = 25 If somebody could give me advice how to solve this problem I would be very glad.
 
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