A positive lens has a focal length of 12cm. An object is located a distance of 3 cm from the lens. How far is the lens from the image? Is the image real or virtual, erect or inverted? My attempt f = +12cm o = +3cm i =? 1/o + 1/I = 1/f 1/i = 1/f – 1/o = 1/12cm – 1/3cm = 1/12 – 4/12 = - (3/12) i = -4cm on the same side of the object. Since the object lies in within the focal point, the image is virtual and erect.