Rearranging Young's Modulus Equation for Force: Help Needed!

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To rearrange the Young's Modulus equation E = (F*L)/(A*ΔL) for force (F), the correct approach involves multiplying both sides by the denominator (A*ΔL) and then dividing by L. The final rearranged equation is F = E*(A*ΔL)/L. It is important to use parentheses correctly to avoid misinterpretation of the equation. Clear communication of the equation format is essential for accurate understanding and solving.
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Homework Statement


Hi all I'm new and wondering if you could help me rearrange this equation for a Young Modulus question:


Homework Equations


Equation for Young Modulus is E = F*L/A*ΔL

* is multiplied
/ is divide

How can I make F the subject of this equation?

The Attempt at a Solution


I have attempted but not very good at rearranging, I managed to get F = E*L/A*ΔL
but that is wrong I think.

All help would be really appreciated, thanks.

Tom
 
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If you have a*b=c then to make a the subject, you divide both sides by b to give \frac{a*b}{b}=\frac{c}{b} and the b's cancel on the left side, so you have a=\frac{c}{b}

If you have \frac{a}{b}=c then multiply both sides by b to make a the subject, giving a=b*c

All you have to do is apply these two ideas to your problem, and you should be set.
 
I've used your idea to come up with:

F = E/L*A*ΔL

Is this right?

Thanks.
 
tommowg said:

Homework Statement


Hi all I'm new and wondering if you could help me rearrange this equation for a Young Modulus question:


Homework Equations


Equation for Young Modulus is E = F*L/A*ΔL
The equation for Young's Modulus is incorrect. The correct version is:
E = \frac{F*L}{A*\Delta L}

I don't doubt that this is what you meant, but when you write a fraction on a single line, you need parentheses to indicate what's in the numerator and what's in the denominator. A better way to write this equation would be E = (F*L)/(A*ΔL).

As you wrote it, the expression on the right side would be interpreted as
F \frac{L}{A} \Delta L
tommowg said:
* is multiplied
/ is divide

How can I make F the subject of this equation?

The Attempt at a Solution


I have attempted but not very good at rearranging, I managed to get F = E*L/A*ΔL
but that is wrong I think.

All help would be really appreciated, thanks.

Tom
To solve for F, multiply both sides of the equation by the reciprocal of the coefficient of F. The coefficient of F is L/(AΔL).
 
tommowg said:
I've used your idea to come up with:

F = E/L*A*ΔL

Is this right?

Thanks.

Depends, use parenthesis as Mark44 has suggested so I know what your answer actually is.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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