Recoil speed of an atomic nucleus

AI Thread Summary
The discussion revolves around calculating the recoil speed of an atomic nucleus after it emits a gamma ray of 24.0 keV. The nucleus has a mass of 9.53e-26 kg, and the challenge lies in applying the correct physics principles to find the recoil speed. Initially, the poster struggled with the calculations, attempting to equate kinetic energy with rest energy and gamma ray energy without success. Guidance was provided to use conservation of momentum and the photon momentum formula to solve the problem. Ultimately, the correct recoil speed of the nucleus is determined to be 134 m/s.
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Homework Statement



An atomic nucleus is in an excited state. It decays to its ground state with the emission of a gamma ray having energy, Egamma = 24.0 keV. The nucleus has a mass of 9.53e-26 kg. What is the recoil speed of the nucleus? (Note: This may be an inelastic collision)

Homework Equations


1 eV = 1.6e-19 J

The Attempt at a Solution


I tried setting the final kinetic equal to the rest energy, and I tried setting it equal to the energy of the gamma ray, and I can't get the answer. The answer key lists the correct answer as 134 m/s, and I have no idea how to get to that.
 
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Why not use conservation of momentum?
Use the special formula for the momentum of a photon, using its energy to calculate its momentum.
 
Thank you, I got it now :)
 
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