Engineering Rectifier Circuit, graph (output wave)

AI Thread Summary
The discussion revolves around understanding the output waveform of a rectifier circuit and the voltage thresholds involved. The user questions why the circuit is active only when the input voltage reaches 4 volts, speculating whether this is due to the sum of the threshold voltages of the diodes. They note that only two diodes are active at any given time during the input wave peaks, leading to confusion about the voltage calculation. There is also a suggestion that the output should reflect +/-2V rather than +4V, indicating a potential misunderstanding of the waveform representation. The conversation highlights the complexities of analyzing rectifier circuits and the importance of accurately interpreting voltage levels in circuit diagrams.
calvert11
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Homework Statement


Sketch the output waveform:

http://img7.imageshack.us/img7/3774/recgraph.jpg
(The coloured lines I added myself)

Homework Equations



Nothing which applies, I think.

The Attempt at a Solution



The answer has already been provided. I just have a concept question.

The full rectifier circuit is active only where the input voltage is 4 or greater (marked in blue). But why 4?

Is it simply the sum of the 4 diode's threshold voltages (marked in red), that is, 1+1+1+1=4?

But only 2 diodes are active at a time (at each peak or valley of the input wave), right? So, why isn't it 1+1=2 instead?

Or am I on the wrong track entirely?
 
Last edited by a moderator:
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calvert11 said:

Homework Statement


Sketch the output waveform:

http://img7.imageshack.us/img7/3774/recgraph.jpg
(The coloured lines I added myself)


Homework Equations



Nothing which applies, I think.

The Attempt at a Solution



The answer has already been provided. I just have a concept question.

The full rectifier circuit is active only where the input voltage is 4 or greater (marked in blue). But why 4?

Is it simply the sum of the 4 diode's threshold voltages (marked in red), that is, 1+1+1+1=4?

But only 2 diodes are active at a time (at each peak or valley of the input wave), right? So, why isn't it 1+1=2 instead?

Or am I on the wrong track entirely?

I believe it should be 2V in the + direction and 2V in the - direction. Is there a chance that is where they got the 4? It still shoule be shown as +/-2V on the triangle wave, though, not +4V. Was that picture part of the solution, or an interpretation of a written answer?
 
Last edited by a moderator:

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