Recursive sequence terms don't cancel

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Homework Statement



The following series is a telescopic series. Find the exact sum of the series by performing a partial fraction decomposition and generalizing the formula for the nth partial sum Sn.

problem.png


Homework Equations


The Attempt at a Solution



3n + 2 = A(n+1)(n+2) + B(n)(n+2) + C(n)(n+1)
n = 0 → 2 = 2A → A = 1
n = -1 → -1 = -B → B = 1
n = -2 → -4 = 2C → C = -2

(3n+2)/(n(n+1)(n+2)) = 1/n + 1/(n+1) + 2/(n+2)

=> Sn = ... = 1 + 1/2 + 1/3 + ... + 1/n + 2/3 + 2/5 + 2/7 + ... + 1/(2n + 1)

I don't see the terms cancel. Did i do something wrong?

Thanks
 
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You forgot about the minus, dude! C=-2 :D
 
Ah, sorry about that, i did have a minus in my original work, typo o_o
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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