Reducing Resistance: True/False Answers

  • Thread starter Thread starter BMWPower06
  • Start date Start date
  • Tags Tags
    Resistance
AI Thread Summary
To reduce the resistance of a tungsten wire, using a piece of copper wire with the same dimensions is true, as copper has a lower resistivity. Increasing the temperature of the wire is false, as higher temperatures increase resistance. Using a thicker piece of tungsten wire is true because it increases the cross-sectional area, thus decreasing resistance. Using a longer piece of tungsten wire is false, as it increases resistance due to greater length. Decreasing the voltage between the ends of the wire is also false, since lower voltage would decrease current, not resistance.
BMWPower06
Messages
92
Reaction score
0

Homework Statement


You have a tungsten wire with a certain length and cross-sectional area. This wire has a resistance R. If you wanted to make a new wire with a SMALLER resistance, which of the following changes would accomplish that objective?
True False use a piece of copper wire instead, with the same length and cross-sectional area
True False increase the temperature of the wire
True False use a thicker piece of tungsten wire, with the same length
True False use a longer piece of tungsten wire, with the same cross-sectional area
True False decrease the voltage between the ends of the wire


Homework Equations


V=IR
R=p(L/A)


The Attempt at a Solution


My answers are in bold, atleast one of them is wrong, but i do not know which one, can anyone help out?

Reason for answers:
1. Copper wire has a lower p so the R will be lower
2. Increasing Temp, increases the R
3. Increases A, which decreases R
4. Increases L which increases R
5. R=V/I so a lower V would mean a smaller R

I can't figure out which answer is wrong, any help?
 
Physics news on Phys.org
Anyone know what I am doing wrong?
 
Think really hard about 5) again. Decreasing V decreases I, not R.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top