Reflection of a falling object on an Inclined Plane

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Homework Help Overview

The discussion revolves around a physics problem involving the reflection of a ball on a smooth inclined plane after it falls and rebounds elastically. The problem is situated within the context of kinematics and conservation laws.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the angles of incidence and reflection, questioning how to determine the angle at which the ball rebounds. There is discussion about the conservation of momentum and the components of momentum before and after the collision with the inclined plane.

Discussion Status

Participants are actively engaging with the problem, offering insights about momentum components and the geometry involved in the reflection process. Some have provided guidance on how to approach the problem using vector components, while others are clarifying the relationships between angles.

Contextual Notes

There is an emphasis on understanding the geometry of the situation, particularly regarding the angles involved in the collision and the implications of conservation laws. The discussion reflects a mix of attempts to apply theoretical concepts to the specific problem at hand.

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Homework Statement


(Irodov - Problems in General Physics - 1-31)
A ball starts falling with zero initial velocity on a smooth inclined plane forming an angle α with the horizontal. Having fallen the distance h, the ball rebounds elastically off the inclined plane. At what distance from the impact point will the ball rebound for the second time?

Homework Equations


Kinematic Equations, Conservation laws

The Attempt at a Solution


I can solve this question if I can get one piece of information - the angle with the inclined plane with which the ball recoils. Using geometry I found that the incoming ball makes an angle 90+α with the plane. However I can't find the recoil angle. I suppose application of the conservation laws is required, but they bear no result for me - any clues on how to proceed?
 
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When the ball reaches the surface, the normal force acts on it and makes it reflect. The normal force changes the normal component of the momentum, but the component parallel with the incline is conserved.
The situation is completely analogous to the reflection of light. Image a light ray falling vertically onto a mirror that makes an angle α with the horizontal. What do you know about the angle of reflection?

ehild
 
The angle of refraction is equal to the angle of incidence...so here the angle with the normal to the plane must be same before and after reflection. But what do you mean by component parallel to the incline? Shouldn't it be zero, as the ball is simply falling downwards?
 
The momentum is vertical, and the vertical direction makes an angle 90+α with the incline, as you found it out already. The momentum has a parallel component with respect to the plane which is unchanged during the collision.

ehild
 
Ok I get what you meant. Before the impact the ball has an angle α with the normal to the incline. If I set up a coordinate system with the y-axis as the normal to the incline and the x-axis as surface of the incline, I can write the momentum before the collision. How do I use this to explicitly show the angle after collision?
 
What are the x and y components of the momentum before the collision in terms of the angle α?
After collision, the x component stays the same, the y component changes sign. What will be the direction of the momentum after collision? Make a drawing, you will see at once.

ehild
 
I can see from the drawing through vector addition, but not from the algebra of it. Since the ball makes an angle 90+α with the plane, the angle with the normal is α. If I resolve the components along these axes the x-component would be mvsin(α) and the y would be -mvcos(α). If the angle after recoiling is θ, the components would be mvsin(θ) and mvcos(θ). If I equate these two using what you said I just get θ=α. So I must have resolved the momentum wrongly?
 
sinα=sinθ; -cosα=cosθ ----> θ=180°-α.

ehild
 

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Ok I get it - thanks for the help!
 
  • #10
Irodov ... i miss my school days :(
 

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