Refocusing of paraxial electron from electron gun

AI Thread Summary
The discussion focuses on the refocusing of paraxial electrons emitted from an electron gun as they pass through a magnetic field. It outlines the relationship between the electrons' acceleration, potential difference, and the magnetic field, leading to the derivation of the distance where the electrons refocus on the X-axis. The key equation derived is d = sqrt(8π²mV/eB²), which corrects an earlier miscalculation. The contributors clarify the use of cyclotron frequency and the time period in the calculations. The conversation emphasizes the importance of accurately applying physical principles to arrive at the correct formula.
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Homework Statement


Electrons emitted with negligible speed from an electron gun are accelerated through a potential difference v along the X-axis. These electrons emerge from a narrow hole into a uniform magnetic field B directed along this axis. However, some of the electrons emerging from the hole make slightly divergent angles as shown in figure. Show that these paraxial electrons are refocused on the X-axis at a distance

sqrt:(8.pi^2.m.V/e.B^2).

Homework Equations

The Attempt at a Solution



m.w^2.r =B.e.V

w= B.e/m ... cyclotron frequency

T= 2.pi.m/B.e

e.V/m = f(acc).d => f= e.V/m.d

d= 1/2.f.T^2 = 1/2. e.V/m.d . 4.pi^2.m^2/B^2.e^2

=> d=sqrt:(2.pi^2.m.V/B^2.e)

2 should be 8 in the actual answer.

Where did I go wrong?
 

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W = qV (W=work, V=potential difference)
(mv^2)/2 = qV (v=velocity)
v = sqrt.(2qV/m)

now, time period, T = 2.pi.m/Be
so, d = v.T
d = sqrt.(8.pi^2.m.V/B^2.e)
:)
 
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