Refrigeration: The Equivalent Rate of Transport of Heat in Watts?

[chunkytuna21]

A 1.2 ton air conditioner has the capacity to freeze 2400 lb of ice at 0°C in a day. What is the equivalent rate of transport of heat in watts?


QH(out)= QL(in) + Wi
Coefficient of Performance= QL/ (QH-QL)
Coefficient of Performance of an Ideal System: TL/ (TH-TL)
QL/QH= TL/TH


I really don't know where to begin with this problem. I know 1.2 tons is equal to 2400lbs. So, the air conditioner and the amount of meat it freezes is a 1 to 1 ratio, but what does any of that have to do with the problem? I'm not given the heat-out or heat-in so how could I possibly calculate the transport of heat in watts? The solution to a similar problem (1 ton air conditioner and 2000lbs of meat is 3.5kW), but I need to know how to solve these type of problems.
Any help would be greatly appreciated!

 

[CFDFEAGURU]

Take a good look at the definition of "1 ton of Refrigeration". Find out how many kJ/s or (Watts) that one ton of refrigeration is equivalent to.

Thanks
Matt

 

[chunkytuna21]

Thanks! That was a lot simpler than I expected it to be.

 

[CFDFEAGURU]

Glad that I could help.

Thanks
Matt