Regarding Fluids and hydrostatic force ratios

AI Thread Summary
The discussion focuses on calculating the ratio of hydrostatic force on the bottom of a cylindrical barrel to the gravitational force of the water it contains. The user has provided dimensions for the barrel and an open tube, noting that the expected answer for the ratio is 2. Initial calculations for the volume of the barrel and the weight of the water were attempted, but the user encountered difficulties, particularly with the tube's contribution. There is uncertainty regarding the conversion of area to radius and how to incorporate the tube's cross-sectional area into the calculations. Clarification and guidance on these calculations are sought to achieve the correct ratio.
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An open tube of length L = 1.8 m and cross-sectional area A = 4.6 cm^2 is fixed to the top of a cylindrical barrel of diameter D= 1.2m and height H=1.8 m

The barrel and the tube are filled with water (to the top of the tube). Calculate the ratio of hydrostatic force on the bottom of the barrel to the gravitational force on the water contained in the barrel. Ignore atmospheric pressure for this question.

Homework Equations


P= patm + pgh
Weight=mg=pVg

The Attempt at a Solution



So I tried calculating the volume of the cylinder, tube then subbing it into the equation
Weight=mg=pVg
however it did not work properly as the answer is supposed to be 2.

Did i convert the Area to Radius wrong? Or is there another way I am supposed to go about thisI set up my ratio as = Weight of Barrel + Tube / Weight of barrel only

V of barrel = Pi * (0.6)^2 * 1.8 = 2.03575204
I subbed this into W=mg=pVg = 1000 g/m^3 * 2.03575204 * 9.8 m/s^2
W=19950

I'm not sure how to go about the tube part as it given us the cross sectional area
 
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can someone please direct me in the right direction
 

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