Relate Magnetic Field, Rotations, and Length of Area in Spin 1/2 Systems?

Cosmossos
Messages
100
Reaction score
0
Here is the problem:
untitled.JPG


How can relate the magnetic field and the rotations and then the length of the area? I only know that 2pi rotation give the initial state a pi phase but that's all.
where the hell I get the length from?

thanks
 
Physics news on Phys.org
This is just a time evolution problem. You know the initial wavevector will evolve in time according to:

|\psi(t)\rangle = \exp(\frac{-iHt}{\hbar})|\psi(0)\rangle

Use the hamiltonian for a spin in a magnetic field. It will look very similar to the rotation generator. Also you know the time the particle is in the magnetic field knowing its velocity.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top