Related rates - finding hypotenuse of triangle

cmkluza
Messages
118
Reaction score
1

Homework Statement


A plane flying horizontally at an altitude of 3 mi and a speed of 480 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 4 mi away from the station. (Round your answer to the nearest whole number.)

Homework Equations


##a^2=b^2+c^2## where ##a## is the hypotenuse of a triangle.

The Attempt at a Solution


I started by relating the given variables as follows
  • Altitude is a constant of 3 mi
  • Horizontal distance of the plane will be ##x##. We measure when ##x=4## miles.
  • Distance from the plane to the radar station will be ##y##. We measure when ##y^2=4^2+3^2 \longrightarrow y=5## miles.
  • Change in horizontal distance will be ##\frac{dx}{dt}## We are given that this is 480 miles/hour.
We have ##y^2=x^2+3^2##. Taking the derivative with respect to time gives ##2y\times\frac{dy}{dt}=2x\times\frac{dx}{dt}+0##. Substituting in known values gives: ##2(5)\times\frac{dy}{dt}=2(4)(480) \longrightarrow \frac{dy}{dt}=\frac{4\times480}{5}=384##. Yet this is not the answer.

Where am I going wrong? I've actually drawn out the triangle and variables, and I'm fairly stuck as to which part I'm messing up. Any insight will be appreciated!
 
Physics news on Phys.org
How did "4 mi away from the station" become only the horizontal component of how far the plane is away from the station?
 
phinds said:
How did "4 mi away from the station" become only the horizontal component of how far the plane is away from the station?
Looks like I totally misread the question. I thought that the problem statement stated 4 to be the distance traveled in the x direction, not the distance between the plane and the station. That's cleared everything up.

Using the above information, the value for ##x## is ##\sqrt{4^2-3^2}=\sqrt{7}##. Plugging the correct values into my above derivative gives the correct answer to this problem: ##2(4)\times\frac{dy}{dt}=2(\sqrt{7})(480)\longrightarrow\frac{dy}{dt}=\frac{\sqrt{7}\times480}{4}\approx317##.

Thanks for pointing that out!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top