Related rates of resistors

  • Thread starter Rasine
  • Start date
  • #1
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If two resistors with resistances and are connected in parallel, as in the figure, then the total resistance R measured in ohms , is given by 1/R=1/R1+1/R2. If and are increasing at rates of .6 and .7 respectively, how fast is R changing when R1=80 and R2=100?

so i take the derivative of the function which is (-1/R^2)dR/dt=(-1/R1^2)dR1/dt-(1/R2)dR2/dt

and then can calculate R to be 1/180 and i know R1, R2, and dR1/dt=.6 and
dR2/dt=.7

i get 5.052E-9 for dR/dt....which is not right

please help me
 

Answers and Replies

  • #2
Curious3141
Homework Helper
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1/100 + 1/80 is not 1/180.

Your derivative is correct (except for the typo where you left out the square on the R2 term). Check your algebra, and it should work out.
 
  • #3
AlephZero
Science Advisor
Homework Helper
6,994
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R is not equal to 1/180.

1/80 + 1/100 does not equal 1/(80+100) = 1/180

.. and also the formula says 1/R = 1/R1 + 1/R2 not R = 1/R1 + 1/R2
 

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