Relating escape velocity equations

AI Thread Summary
The discussion focuses on understanding the relationship between the escape velocity equations sqrt(2GM/r) and sqrt(2gr). Participants emphasize that both equations represent the same concept, but the challenge lies in deriving one from the other. The gravitational force equations, F = -Gm1m2/r^2 and F = mg, are equated to find a connection. The key step involves substituting g with Gm/r^2 to bridge the two equations. The conversation highlights the importance of recognizing the equivalence of gravitational force in different contexts.
calfly
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Homework Statement


I'm having a hard time relating the escape velocity equations, sqrt(2GM/r) to sqrt(2gr)

The Attempt at a Solution


I know that both equations mean the same thing, but I can't figure out how to get from the first equation to the second
 
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Do you know the equation for the gravitational force between two objects (in space)?
 
F=-Gm1m2/r^2
 
Yep, and I assume you know the equation for the gravitational force acting on an object on (or near) the surface of the Earth... now, the force should be the same whether you calculate it using one equation or the other. So set the two forces equal to each other and see what you get.
 
err, I think this is where I'm stuck at. if an object is right on the surface of the Earth then I guess the gravitational force would look the same as the general equation-ish
F=-Gm(earth)m(object)/R(earth)^2. I'm not quite sure what I'm looking at when I set them equal to each other.
 
calfly said:
F=-Gm(earth)m(object)/R(earth)^2
OK, well, that's right... now, when I mentioned the equation for gravitational force on an object near the surface of the Earth, I was trying to get you to think of the equation you used before you learned about F = -Gm_1m_2/r^2. Do you remember?
 
Ah I think I'm starting to get it but I'm making a math error somewhere i think,
okay so I set f = mg = -Gm1m/r^2, cancel out "m", --> g=-Gm1/r^2.

now I got to fit that into sqrt(2Gm/R) but that does not get sqrt(2gr)?
err i think.
 
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Welcome to PF!

Hi calfly! Welcome to PF! :smile:

(have a square-root: √ and try using the X2 tag just above the Reply box :wink:)
calfly said:
Ah I think I'm starting to get it but I'm making a math error somewhere i think,
okay so I set f = mg = -Gm1m/r^2, cancel out "m", --> g=-Gm1/r^2.

now I got to fit that into sqrt(2Gm/R) but that does not get sqrt(2gr)?
err i think.

( diazona :smile: seems to be offline, so …)

Put g = Gm/r2 into √(2gr). :wink:
 
Just what I was going to say :wink: thanks for jumping in on that, tiny-tim.
 
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