Relating schematic equation to find total distance

  • Thread starter Thread starter 13rainboy
  • Start date Start date
  • Tags Tags
    Schematic
AI Thread Summary
The discussion focuses on using the equation for vertical motion to analyze the total distance traveled by a water balloon shot into the air. The equation includes variables for vertical displacement but does not directly account for horizontal distance. To find the total distance, one must consider both the vertical and horizontal components separately. The vertical displacement is determined by the equation, while the horizontal distance requires knowledge of the time of flight and initial horizontal velocity. Understanding the distinction between vertical and horizontal motion is crucial for accurately graphing the total distance traveled.
13rainboy
Messages
1
Reaction score
0
I need help with this, or for that fact i need to know if this is even possible. I'm using the equation of change in x equals one half at squared plus v not t plus initial height. Now using this, we shot water balloons. we found all the variables necessary to complete the equation. the only problem, is that now we want to find a graph of the equation where we can find the total distance traveled by the water balloon. is it possible to find this since we have a distance relating to y and a distance relating to x in the same equation? any help would be great!
 
Physics news on Phys.org
delta x and h are both variables to y, really, not x. The at^2 equation describes the displacement of the object in the vertical direction, not the the horizontal direction. If you you were to graph this equation it would show the distance traveled by the object in the y-direction. To find the distance traveled in the x-direction, you just need the time traveled by the object as well as it's initial velocity in the horizontal direction.
 
comparing a flat solar panel of area 2π r² and a hemisphere of the same area, the hemispherical solar panel would only occupy the area π r² of while the flat panel would occupy an entire 2π r² of land. wouldn't the hemispherical version have the same area of panel exposed to the sun, occupy less land space and can therefore increase the number of panels one land can have fitted? this would increase the power output proportionally as well. when I searched it up I wasn't satisfied with...
Back
Top