VishalB95 said:
But i don't understand what you said about torque getting less but speed gets higher. How does that happen?
Observe zanick's beginning premise: constant power.
zanick said:
with a constant power , the torque at the wheels goes down as you go faster, through all the gears until you reach your top speed (terminal velocity). where the torque will be at the lowest but the speed will be a the greatest. (and the power is the same as when you started ).
That's not the simplest of analogies.
for It to be true
your input torque must be shared between
accelerating the vehicle, F = ma
and opposing the force of drag, drag usually being proportional to square of speed
So ,the vehicle stops accelerating when force and drag become equal.
Force is in proportion to torque not power.
If you'll go way back in the thread
and come to believe that
power = torque X RPM X (some constant to adjust for units, si or whatever)
your question will be answered
power = torque X RPM X constant
set power to any number you like, double RPM, solve for new torque.
For fun let's set power equal to "constant" .
power = constant
and since also power = torque X RPM X constant
we can substitute 'constant' for power
constant = torque X RPM X constant
divide both sides by constant
1= torque X RPM
torque = 1/RPM
if RPM = 1, torque = 1
if RPM = 2, torque = ½it's that simple. Really.