Relationship betweem angle of a ramp and tension in rope

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The discussion focuses on the relationship between the angle of a ramp and the tension in a rope connected to a cart. As the ramp angle increases, tension rises proportionally until reaching 45 degrees, after which it approaches 9.8 N. This behavior is explained by the tension being equal to the mass of the cart multiplied by the sine of the ramp angle. For small angles, the sine of the angle closely approximates the angle itself, but this approximation becomes less accurate as the angle increases, particularly around 45 degrees. The mathematical relationship highlights the significance of the angle's sine value in determining tension in this scenario.
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In my physics class we did a lab where we attached one end of a string to a .5 kg cart and the other end to a force meter which was all on a ramp. As we increased the angle of the ramp, the tension increased proportionally until the angle reached 45 degrees. From 45 degrees to 90 degrees, as we increased the angle, the tension approached m9.8. I understand why it approaches m9.8, but why does that start at 45 degrees?
 
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The tension on the rope is equal to the mass of the cart times the sine of the angle of the ramp. For small angles the angle, in radians, is approximately equal to the sine of the angle. As the angle becomes larger the difference becomes larger and it begins to become significant around Pi/4 which is 45°. Try it with a calculator and you'll see what I mean. Set it to radians and enter small values and calculate the sine and you'll see that for small radians angle=sine(angle).

http://en.wikipedia.org/wiki/Small-angle_approximation
 
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