Relationship between a V and R?

Thread starter velocity
Start date Mar 22, 2007
Tags

Relationship

AI Thread Summary

The discussion centers on understanding the relationship between voltage and resistance in a series circuit. Ohm's law is highlighted, stating that voltage (V) equals current (I) multiplied by resistance (R). Participants seek clarification on whether the inquiry pertains to measuring voltage with a voltmeter or understanding the current flow. The conversation emphasizes the fundamental principles of circuit theory. Overall, the relationship between voltage and resistance is clearly defined by Ohm's law.

Mar 22, 2007

velocity

Is there any specific method of finding the relationship between a voltage and a resistor in series? :redface:

Last edited: Mar 22, 2007

Physics news on Phys.org

Mar 22, 2007

dt19

do you mean a voltmeter? what sort of relationship do you mean - current through it, or what?

Mar 26, 2007

velocity

Re-phrase

The relationship between potential difference (voltage) and resistance in a series circuit?

Mar 26, 2007

hage567

Homework Helper

Well Ohm’s law states V=I*R. Where V is the voltage, I is the current, and R is the resistance.

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »