Relationship between potential and induced emf?

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Homework Help Overview

The discussion revolves around the relationship between potential and induced electromotive force (emf) in a semicircular wire moving through a magnetic field. The problem involves determining the induced emf and the potential difference between two points on the wire.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the application of the induced emf equation in the context of an open circuit. Questions arise about the nature of magnetic flux linkage and the implications of induced current direction on potential differences.

Discussion Status

The discussion is active, with participants questioning the assumptions about the circuit's closure and the nature of forces acting on the wire. Some guidance has been offered regarding the interpretation of length in the emf equation, but no consensus has been reached on the implications of induced current direction.

Contextual Notes

Participants are navigating the complexities of induced emf in a non-closed circuit and the definitions of potential in relation to induced current. There are also considerations regarding the interpretation of forces in the context of motion through a magnetic field.

Yoriko
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Homework Statement



[PLAIN]http://img220.imageshack.us/img220/2589/44045733.png

Semicircular wire MN of diameter L moves with speed v perpendicularly through a uniform magnetic field of strength B.

1. Find the magnitude of the induced emf generated between M and N.
2. State whether M or N is at a higher potential.

Homework Equations



E = BLv

The Attempt at a Solution



1. Given answer: Induced emf = BLv

However, I was wondering if you can use that equation even if it's not a closed circuit?
In the semicircular wire, there shouldn't be magnetic flux linkage. And even if there was, there is no change in magnetic flux linkage.

2. N is at a higher potential

There is opposing force that resists the motion of the wire (:confused: is this reason correct?), which, by Fleming's left hand rule, results in an induced current (if the circuit were to be closed) flowing from M to N. Thus, N is at higher potential as a result of the induced "current".

However, I know that current flows from higher potential to lower potential. So is it right to say that in the case of an induced current, if it flows from M to N, N is at a higher potential?
 
Last edited by a moderator:
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However, I was wondering if you can use that equation even if it's not a closed circuit?

Sure, you can, you have to.
Just be careful what "length" is.

If it was a closed circuit of zero resistance, there would be no voltage at all.
V=RI, R=0, so V=0 (for closed loops of zero resistance)

However, I know that current flows from higher potential to lower potential. So is it right to say that in the case of an induced current, if it flows from M to N, N is at a higher potential?

Pay attention to the charge sign.

There is opposing force that resists the motion of the wire

No there's no opposing force.
 
No there's no opposing force.

Then how is there an induced emf?

[PLAIN]http://img207.imageshack.us/img207/5853/93128344.png

Do you take "Force" to be in direction of the velocity?
 
Last edited by a moderator:
i know the thread is old but i have a question
what shall we take as a length to calculate E, the length πr of the arc or the length 2r of the line segment and why?
thanks a lot
 

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