Relationship between potential and induced emf?

AI Thread Summary
The discussion focuses on the induced electromotive force (emf) in a semicircular wire moving through a magnetic field. The induced emf is calculated using the formula E = BLv, which is applicable even if the circuit is not closed, though care must be taken regarding the length used in the calculation. It is established that point N is at a higher potential than point M due to the direction of the induced current, which flows from M to N. The conversation also addresses the concept of opposing forces and clarifies that there is no opposing force acting on the wire despite the presence of induced emf. Overall, the relationship between potential and induced emf is explored in the context of motion through a magnetic field.
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Homework Statement



[PLAIN]http://img220.imageshack.us/img220/2589/44045733.png

Semicircular wire MN of diameter L moves with speed v perpendicularly through a uniform magnetic field of strength B.

1. Find the magnitude of the induced emf generated between M and N.
2. State whether M or N is at a higher potential.

Homework Equations



E = BLv

The Attempt at a Solution



1. Given answer: Induced emf = BLv

However, I was wondering if you can use that equation even if it's not a closed circuit?
In the semicircular wire, there shouldn't be magnetic flux linkage. And even if there was, there is no change in magnetic flux linkage.

2. N is at a higher potential

There is opposing force that resists the motion of the wire (:confused: is this reason correct?), which, by Fleming's left hand rule, results in an induced current (if the circuit were to be closed) flowing from M to N. Thus, N is at higher potential as a result of the induced "current".

However, I know that current flows from higher potential to lower potential. So is it right to say that in the case of an induced current, if it flows from M to N, N is at a higher potential?
 
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However, I was wondering if you can use that equation even if it's not a closed circuit?

Sure, you can, you have to.
Just be careful what "length" is.

If it was a closed circuit of zero resistance, there would be no voltage at all.
V=RI, R=0, so V=0 (for closed loops of zero resistance)

However, I know that current flows from higher potential to lower potential. So is it right to say that in the case of an induced current, if it flows from M to N, N is at a higher potential?

Pay attention to the charge sign.

There is opposing force that resists the motion of the wire

No there's no opposing force.
 
No there's no opposing force.

Then how is there an induced emf?

[PLAIN]http://img207.imageshack.us/img207/5853/93128344.png

Do you take "Force" to be in direction of the velocity?
 
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i know the thread is old but i have a question
what shall we take as a length to calculate E, the length πr of the arc or the length 2r of the line segment and why?
thanks a lot
 
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