Relative Motion Homework: Snow Falling Angle at 6.9 m/s, 79 km/h

AI Thread Summary
Snow is falling vertically at a speed of 6.9 m/s while a car is traveling at 79 km/h, which converts to approximately 21.94 m/s. To determine the angle at which the snowflakes appear to fall from the driver's perspective, both vertical and horizontal speeds must be considered. The vertical motion of the snow and the horizontal motion of the car create a resultant angle. The problem requires calculating this angle using trigonometric relationships. Understanding the relationship between these two velocities is key to solving the homework question.
lauriecherie
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Homework Statement


Snow is falling vertically at a constant speed of 6.9 m/s. At what angle from the vertical do the snowflakes appear to be falling as viewed by the driver of a car traveling on a straight, level road with a speed of 79 km/h? _________ degrees


Homework Equations





The Attempt at a Solution


No idea where to begin! Help please!
 
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Start with how many m/s the car is going.
 
LowlyPion said:
Start with how many m/s the car is going.

Ok so that is 21.94 m/s right? I don't know what to do with this info! I am so lost!
 
lauriecherie said:
Ok so that is 21.94 m/s right? I don't know what to do with this info! I am so lost!

The snow is falling vertically at 6.9m/s.

As you look out the window it is also moving horizontally at 21.94m/s

Let's see. Vertically ... horizontally ... hmmm. Think there might be an angle in there somewhere?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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