Relative Velocities: What is the direction of the plank's movement on the ice?

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The discussion centers on a physics problem involving a girl walking on a plank on a frictionless surface. The girl has a mass of 45.0 kg and walks at a velocity of 1.52 m/s relative to the plank, which has a mass of 163 kg. To find the girl's velocity relative to the ice, momentum conservation principles are applied, but there is confusion about expressing her velocity correctly. The plank will move in the opposite direction to conserve momentum as the girl walks. The key takeaway is that the direction of the plank's movement is opposite to that of the girl's movement on the plank.
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Homework Statement


A 45.0 kg girl is standing on a 163 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.52 m/s relative to the plank.
(a) What is her velocity relative to the surface of ice?
(b) What is the velocity of the plank relative to the surface of ice?


Homework Equations


m1v1i + m2v2i = m1v1f + m2v2f


The Attempt at a Solution


a. (45.0 kg)(0 m/s) + (163 kg)(0 m/s) = (45.0 kg)(v1f) + (163 kg)(1.52 m/s)
v1f=5.51 m/s
 
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Good beginning, but you need to express the velocity of the girl relative to the ground, not relative to the plank when you conserve momentum.
 
so how would I go about doing that?
 
Say the girl is moving left to right. In what direction is the plank moving?
 
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