Relativity and Lorentz Transformations

AI Thread Summary
Spaceship A, traveling at 0.6c, has a proper length of 30m, and a light flash occurs when it passes spaceship B. For part a, the time reading at the rear of spaceship A when the light reaches it is calculated using its proper length and the speed of light, yielding t1' = 30m/c. In part b, the Lorentz transformation is applied to find the time reading on spaceship B when the light reaches the rear of A, resulting in t1 = 5.0 x 10^-8 s. The calculations for both parts are confirmed to be correct. Understanding these concepts is essential for mastering relativistic physics.
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Homework Statement


Spaceship A of length 30m travels at 0.6c past spaceship B. Clocks in frame S' of spaceship A and S of spaceship B are synchronised within their respective frames of reference and are set to zero, so that t' = t = 0 at the instant the front of spaceship A passes the rear of spaceship B located at x' = x = 0. At this time a light flashes at the front of spaceship A.

a. When the light flash reaches the rear of spaceship A, what is the reading of a clock there?
b. What is the reading on the clock on spaceship B when according to an observer on B, the flash reaches the rear of A?

Homework Equations


Lorentz transformation formulas

The Attempt at a Solution


a. From spaceship A's POV, it is stationary. It measures proper length. Thus time t1' = 30m / speed of light. Is this correct?

b. Using Lorentz transformation of time,
t = γ(t' + ux'/c2)

x1' = -30, u = 0.6c and t1' from answer in a, I got t1 = 5.0*10-8 s. Does this work?

Thanks!
 
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little neutrino said:

Homework Statement


Spaceship A of length 30m travels at 0.6c past spaceship B. Clocks in frame S' of spaceship A and S of spaceship B are synchronised within their respective frames of reference and are set to zero, so that t' = t = 0 at the instant the front of spaceship A passes the rear of spaceship B located at x' = x = 0. At this time a light flashes at the front of spaceship A.

a. When the light flash reaches the rear of spaceship A, what is the reading of a clock there?
b. What is the reading on the clock on spaceship B when according to an observer on B, the flash reaches the rear of A?

Homework Equations


Lorentz transformation formulas

The Attempt at a Solution


a. From spaceship A's POV, it is stationary. It measures proper length. Thus time t1' = 30m / speed of light. Is this correct?

b. Using Lorentz transformation of time,
t = γ(t' + ux'/c2)

x1' = -30, u = 0.6c and t1' from answer in a, I got t1 = 5.0*10-8 s. Does this work?

Thanks!
Yes.
 
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