Release Ball to Fall Through Hole on Circular Platform

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To determine when to release the ball so it falls through the hole on the spinning circular platform, first calculate the time it takes for the ball to fall 1.3 meters at a speed of 1.8 m/s, which is approximately 0.72 seconds. During this time, the platform completes a portion of its revolution; since it makes one complete revolution in 2.5 seconds, it will rotate about 28.8 degrees in 0.72 seconds. The hole's position must be adjusted accordingly to account for this rotation. By calculating the distance the disk spins during the fall, the correct release timing can be determined. This problem emphasizes the importance of synchronizing the ball's drop with the platform's rotation.
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A Ball Is Held Above A Spinning Circular Platform. The Ball Is 1.3m Above The Circular Platform That Has A Diameter Of .67m And Makes One Complete Revolution In 2.5 Seconds. If The Platfom Has A Hole On The Edge Where The Fall Can Get Through And The Ball Falls At 1.8 M/s...when Should The Ball Be Release In Order To Go Through The Hole?
 
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This belongs on the homework questions section, and you should make an attempt at the solution before asking for too much help. (Hint, think about the time taken for the ball to fall, and how much the disk will spin in that time).

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i have made a try i even made a drawing but its still hard...
 
Well, calculate t, the time taken for the ball to fall. Then work out how far the disk will spin in that time.

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