Require help for the solution of second order differential equation.

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Homework Help Overview

The discussion revolves around a second order differential equation, which one participant describes as complex and challenging. The original poster seeks assistance in finding a solution to this equation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the origin of the equation and its complexity. Some attempt to solve it by making assumptions, while others question the validity of these assumptions and the boundary conditions involved.

Discussion Status

There is ongoing dialogue with participants sharing their attempts and challenges in solving the equation. Some have offered to explore operative methods, while others have acknowledged their limitations in numerical methods. The discussion remains open with no clear consensus or resolution yet.

Contextual Notes

Participants mention specific boundary conditions and assumptions related to the equation, indicating that these factors may influence their approaches to finding a solution.

Sagaralok
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Dear Friends i am lookin g for the solution for second order differential equation. will anyone please help me to solve this problem.
 

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From where did that equation came from! its like a monster ;) no if i find an operative way of solving it i tell you
 
Just to be sure:

[tex]\frac{\frac{d^2y}{dx^2}}{[\,( 1\,+\,(\frac{dy}{dx})^2 )^{3/2}\,]} + \frac{\frac{dy}{dx}}{[\,x\,( 1\,+\,(\frac{dy}{dx})^2 )^{1/2}\,] }\;{-\,y} = 0[/tex]

where

[tex]\frac{dy}{dx} = tan \theta\;at\;x = x_o[/tex]

and

[tex]\frac{dy}{dx} \rightarrow 0\; and\;y = 0\;as\;x \rightarrow \infty[/tex]
 
Thank you Zaphys atleast you given reply to me. it is really difficult to solve this i am not getting solution of it.
rest is fine take care


Zaphys said:
From where did that equation came from! its like a monster ;) no if i find an operative way of solving it i tell you
 
You're welcome :)
 
dear friend
i tried to solve it after some assumptions
but my solution is still not satisfying first boundary condition will you please go through it.

rest is fine
take care
sagar
 

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I´m not much versed in numeric methos so here I can't help you. Sorry ;)

Salutations Sagar
 
no problem Zaphys
take care
sagar


Zaphys said:
I´m not much versed in numeric methos so here I can't help you. Sorry ;)

Salutations Sagar
 

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