Resistance in a wire, sanity check about units.

AI Thread Summary
The discussion revolves around calculating the resistance of a wire using the formula R = p*L/A, where resistivity (p), length (L), and cross-sectional area (A) are key factors. The user initially converted units incorrectly, leading to a significant miscalculation of resistance. After clarifying the conversion of resistivity from ohm-cm to ohm-m, the correct resistivity value is established as 4.0 x 10^-9 ohm-m. With the proper values, the resistance calculation yields the accepted answer of 0.0113177 ohms. This highlights the importance of accurate unit conversion in physics problems.
Cade
Messages
90
Reaction score
0

Homework Statement



A x cm long wire has a diameter of y mm and a resistivity of 4.0x10-7 ohm-cm. Calculate its resistance.

Homework Equations



R = p*L/A

The Attempt at a Solution


First, I convert the given information into SI units:
Length = x*10^-2 m
Diameter = y*10^-3 m
Resistivity = 4*10^-5 ohm/m

Next, cross-sectional area of a wire/cylinder is pi*r^2 = pi*(d/2)^2 = (1/4)pi*d^2

R = p*L/A = p*L/((1/4)pi*d^2) = (4 L p)/(d^2 pi)

If x = 20 cm and y = 0.3mm,
R = (4*20*10^-2 *4*10^-5)/((0.3*10^-3)^2*Pi) = 113.177 ohms

Is this correct? My TA told me that I converted the units wrongly, and that the correct answer is 0.0113177 ohms.
 
Physics news on Phys.org
How did you convert 4.0*10-7 ohm-cm to units of ohm-m ?

1 cm = 1*10-2m .
 
4.0*10-7 ohm-cm * 10^-2 m/cm = 4.0*10^-9 ohm-m

Oh, that's the mistake, I did it in the opposite direction.
 
Cade said:
4.0*10-7 ohm-cm * 10^-2 m/cm = 4.0*10^-9 ohm-m

Oh, that's the mistake, I did it in the opposite direction.
And now you should get the accepted answer.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top