Resistor Heat Dissipation (with imaginary numbers)

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SUMMARY

The discussion centers on calculating heat dissipation in an electrical circuit involving imaginary numbers. The current is given as I = (3 + 4j) Amps, and the impedance as Z = (2 + 3j) Ohms. The correct method to find the heat dissipated is by using the magnitude of the current, |I| = 5 Amps, and the real part of the impedance, Re(Z) = 2 Ohms, resulting in a power dissipation of P = (5^2) * 2 = 50 Watts. Additionally, the RMS power formula P_{RMS} = {|I|^2 / 2} |Z| is also mentioned for further clarity.

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derek88
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Friends:

I am wondering about heat dissipation when you have imaginary numbers.

Lets say a current I = (3 + 4j) Amps is going through an impedance Z = (2 + 3j) Ohms. What is the amount of heat dissipated by the impedance?

I think that you take the magnitude of the current, |I| = 5 Amps, and then find the heat dissipated by only the real part of the impedance, Re(Z) = 2. The heat dissipated would be P = (5^2)*2 = 50 W.

Is this correct?

Note: This is not a homework question. This is something I just wanted to verify.
 
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The RMS power is:
[tex]P_{RMS}={|I|^2 \over 2} |Z|[/tex]
 
Last edited:

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