Resultant Force: 40N in Negative X Direction

AI Thread Summary
A particle is in static equilibrium when the resultant force acting on it is zero. To achieve this with two forces of 40N each, one acting 60 degrees above the positive x-axis and the other 60 degrees below the negative x-axis, the resultant force must be calculated. The initial calculation suggests using the Pythagorean theorem to find the magnitude of the resultant force, yielding approximately 56.57N. To maintain static equilibrium, an additional force must counteract this resultant. The discussion emphasizes the importance of vector summation in determining the necessary force for equilibrium.
alexmolinavr6
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Resultant force?

A particle is said to be in static equilibrium if the resultant of all forces is applied to it is zero. Find the force that must be applied to a particle that produces static equilibrium if there are two forces, each of 40N applied so that one acts 60o above the positive x-axis and the other 60 below the negative x-axis.
Give the magnitude of the resultant acting in the negative x direction.

vectors.jpg
 
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alexmolinavr6 said:
A particle is said to be in static equilibrium if the resultant of all forces is applied to it is zero. Find the force that must be applied to a particle that produces static equilibrium if there are two forces, each of 40N applied so that one acts 60o above the positive x-axis and the other 60 below the negative x-axis.
Give the magnitude of the resultant acting in the negative x direction.

vectors.jpg

Welcome to the PF. You need to show us the Relevant Equations and your Attempt at a Solution, before we can be of tutorial help. What can you say about how to start summing and figuring out the vector equations?
 


this is what I was thinking in doing
Taking the magnitude of the given forces

llF1^2ll llF2^2ll

which when plugged in would be something like:

sqrt[(40^2)+(40^2)]

which will give me a F3=56.57N
 

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