Rewriting the derivative of a homogenous function demonstration

bobbarker
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Homework Statement


Suppose that f=f(x1,x2,...,xn) is a homogeneous function of degree r with mixed partial derivative of all orders. Show that

XZivX.png


Can this be generalized?

Homework Equations



We say that a function f is homogeneous of degree r if there exists r such that f(tx1,tx2,...,txn) = tr * f(x1,x2,...,xn)

The Attempt at a Solution


I'm pretty lost on how to show these two. I understand that this is kind of like taking the "second derivative" of f with respect to t, but how do I introduce the t into the sum terms?
 
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bobbarker said:
We say that a function f is homogeneous of degree r if there exists r such that f(tx1,tx2,...,txn) = tr * f(x1,x2,...,xn)

Just start from this equation and derive both sides with respect to t, then set t = 1. The generalization to all derivatives is obvious to you, isn't it?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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