Riemann integral is zero for certain sets

ianchenmu
Messages
7
Reaction score
0

Homework Statement


The question is:

Let ##\pi=\left \{ x\in\mathbb{R}^n\;|\;x=(x_1,...,x_{n-1}, 0) \right \}##. Prove that if ##E\subset\pi## is a closed Jordan domain, and ##f:E\rightarrow\mathbb{R}## is Riemann integrable, then ##\int_{E}f(x)dV=0##.




Homework Equations



n/a

The Attempt at a Solution


(How to relate the condition it's Riemann integrable to the value is ##0##? The textbook I use define ##f## is integrable on ##E## iff ##\;\;\;\;(L)\int_{E}fdV=(U)\int_{E}fdV##)
 
Physics news on Phys.org
What is the definition of "closed Jordan domain"?

Regardless of what the answer to that is, the strategy here should definitely be to prove that given ##\varepsilon>0##, there's an upper sum U and a lower sum L such that ##-\varepsilon<L<U<\varepsilon##. You may want to try this for an especially simple choice of E and f before you try the general case.
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top