Riemann proof effect on factoring composites

Loren Booda
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To what degree would proving the Riemann hypothesis facilitate the factoring of large composites? In other words, how much would a complete (as opposed to "hit-or-miss") knowledge of primes help to reduce the operations needed to factor large composites?
 
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Loren Booda said:
To what degree would proving the Riemann hypothesis facilitate the factoring of large composites? In other words, how much would a complete (as opposed to "hit-or-miss") knowledge of primes help to reduce the operations needed to factor large composites?

Not at all.

It might improve one or two obscure sieving algorithms, though. Maybe the pseudosquare sieve?
 
Consider all primes being initially unknown against a complete knowledge of primes. By what parameter does that knowledge reduce the number of operations to factorize composites.
 
If memory serves, there are some algorithms which are right now probabilistic, but become deterministic if the generalized RH is true.

EDIT: There we go.
 
Dragonfall said:
If memory serves, there are some algorithms which are right now probabilistic, but become deterministic if the generalized RH is true.

EDIT: There we go.

Yes, but the question was about the RH not the GRH. And even under the GRH, the article mentions only one factoring algorithm: the quadratic sieve via Shanks-Tonelli. I'm not even sure how Shanks-Tonelli helps the quadratic sieve, since it needs x^2 = a^2 (mod n) and Shanks-Tonelli finds x^2 = b (mod p) for prime p.
 
Ya I can't figure it out either. Might have to initiate a discussion the talk page.
 
CRGreathouse said:
I'm not even sure how Shanks-Tonelli helps the quadratic sieve, since it needs x^2 = a^2 (mod n) and Shanks-Tonelli finds x^2 = b (mod p) for prime p.
One of the steps in the QS requires you to find square roots mod p, doesn't it?
 
Hurkyl said:
One of the steps in the QS requires you to find square roots mod p, doesn't it?

How much time does that take, asymptotically?
 
CRGreathouse said:
How much time does that take, asymptotically?
Well, you have to solve x²=N (mod p) for every prime p below the smoothness bound. Sounds like a lot.
 

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