Rigid Object In Static Equilibrium

AI Thread Summary
For a rigid object to be in static equilibrium, its center of gravity must be directly over its support point to satisfy the condition \sum \vec{\tau}_{ext}=0. If the center of gravity is outside the support zone, it creates a net torque that can cause the object to tip over. The axis of rotation is located at the contact point with the floor, meaning any displacement of the center of gravity away from this point results in rotational instability. Understanding this principle is crucial for analyzing the stability of various objects. Proper alignment of the center of gravity with the support point ensures equilibrium and prevents tipping.
Bashyboy
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Hello,

I am currently reading the about the topic mentioned in the title of this thread. In my textbook, the author gives the example with the wine-bottle and it's holder (I attached a photo). In this example, the author states that in order for this to be in static equilibrium, the second condition, \sum \vec{\tau}_{ext}=0, which can only be satisfied when the center of gravity of the system is directly over the support point.

Could someone explain why the center of gravity has to be directly over the support?
 

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Ask yourself what would happen if the 'center of gravity' (the effective point at which the force of gravity acts on a rigid body) were to be outside of the support zone. Would there be a net torque? If so, how much and in what direction?
 
Okay, I see, now. So, the axis of rotation is coming out of the computer screen, at the bottom of the piece of wood in contact with floor?
 
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