Rings and Fields: Understanding Polynomials as a Commutative Ring with Unity

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Homework Help Overview

The discussion revolves around whether the set of all polynomials forms a ring and a field, focusing on properties such as commutativity and the existence of a multiplicative identity.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of a ring and field in the context of polynomials, questioning the existence of multiplicative inverses and the implications of polynomial degrees on these properties.

Discussion Status

Some participants have provided insights regarding the identity element and the nature of polynomial multiplication, while others are questioning the conditions under which polynomials can have inverses, indicating a productive exploration of the topic.

Contextual Notes

There is an ongoing discussion about the necessity of rational functions for inverses and the implications of polynomial degree on the existence of such inverses.

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Homework Statement



is the set of all polynomials a ring,and a fieldd.Is is commutative and does it have unity

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The Attempt at a Solution



now if we add or multiply any polynomials we get a polynomial. So it is a ring, but i am not sure what the multiplicative inverse is or whether every non zero element has an inverse to constitute a field.
 
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Multiplication is just ordinary multiplication of polynomials and the identity is the "constant" polynomial p(x)= 1 for all x. Does there exist a polynomial p(x) such that (x-1)(p(x))= 1? Think about the degree of p and what multiplication of polynomials does to degrees.
 
i am thinking that we do not have multiplicative inverses because there is no polynomial that would give one, we would need to use a rational function, is this a correct assesmnent?
 
Yes, but to give a complete answer, you need to say why "no polynomial would give one" (I presume you mean there is no polynomial, p(x), such that (x-1)p(x)= 1.)

Again, think of the "degree" of polynomials. The degree of x- 1 is 1. What could the degree of (x-1)p(x) be? Could it be equal to 0, the degree of the constant polynomial, 1?
 
ok thanks
 

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