RLC circuit

  • Thread starter k31453
  • Start date
  • #1
58
0
[Broken]

This is my question 1.

and this is my question 2.

in a RLC series circuit show above are replaced following : R=500Ω L=0.4mH and C=100pF
the circuit is connected to the terminals of an ac source with an rms voltage of 1V, and a variable frequency calculate the following
A) resonant frequency
ans: f = 1/2*pi*sqrt(LC)
= 1/(2*pi*sqrt(0.0004 * 100 * 10^-12)
= 795.77 Khz

b) the inductive and capacitive reactance at resonance
ans: XL = 2*pi*f*L
= 2*pi* 795.775*10^3*0.0004
= 2000 ohm

Xc = 1/(2*pi*f*C)
= 1/(2*pi* 795.775*10^3 * 100 * 10^-12)
= 1999.9998 ohm

C) the impedance at resonance

ans : impedence of resonance is resistance of circuit : z = R = 500 ohm

D) the rms current at resonance
ans: I = V/R = 1/500 = 0.002A

E) the rms voltage across each element at resonance
Ans: Vr = IR
= 0.002 * 500
= 1V

VL = IXL
= 0.002 * 2000
= 4V

Vc = IXc
= 0.002 * 1999.99
= 3.99998 V

So am i doing it right?? because
i got another reply that says this :

[Broken]
[Broken]
 
Last edited by a moderator:

Answers and Replies

  • #2
1,506
18
In your calculation you have used L = 0.4mH but the printed question has L = 0.4H
 

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