RLC Circuits: Current from Emf at Very Large/Small Freq.

AI Thread Summary
The discussion focuses on determining the current supplied by the emf in an RLC circuit at very high and very low frequencies. At high frequencies, the inductor opposes rapid changes in current, effectively behaving like an open circuit, while the capacitor allows current to pass, leading to minimal impedance. Conversely, at low frequencies, the inductor allows steady current flow, acting like a short circuit, while the capacitor blocks current, resulting in high impedance. The circuit's configuration, including resistances and reactances, influences the overall behavior at these frequency extremes. Understanding these principles is crucial for analyzing RLC circuits under varying frequency conditions.
kevin7913
Messages
4
Reaction score
0

Homework Statement


What is the current supplied by the emf when the frequency is very large and very small?

-------------------------
| |
| ------------------------
| | |
| 100ohm 50ohm
10Vrms | |
| 50mH 20*10^-6F
| | |
| ------------------------
| |
|--------------------------

Homework Equations


Vrms =v/2^(1/2), Z=(R^2 + (XL - Xc)^2)^(1/2), VR =IR, VL =IXL, Vc=IXc

The Attempt at a Solution



I don't know where to start, since they didn't give the frequency.
Please help
 
Physics news on Phys.org
the picture didn't shows up very good, it's a 100ohm and a 50mH in series and parrell with a 50ohm and a 20*10^-6F in series
 
HTML ignores consecutive whitespace.
Using the quote feature, I was able to get your circuit.
Surround by
Code:
 [/ code] (no space in the tag)

crudely,
[code]

[FONT="Arial"]
-------------------------
|                                 |
|                  ------------------------ 
|                  |                               | 
|             100ohm                         50ohm
10Vrms          |                               |
|              50mH                             20*10^-6F
|                  |                               |
|                  ------------------------
|                                   |
|--------------------------
 
Forget equations. Think about how you can replace the capacitor and inductor at high enough and low enough frequencies (ie the limits as f->0 and f->infinity)
 
Last edited:
If the frequency is very high, the supplied voltage is rapidly changing. How does the inductor behave in response to this rapidly changing emf?

If the frequency is very low, the supplied voltage can be approximated as nearly constant over a finite interval of time. How does the inductor behave as a result of this nearly constant source?

Now go back and consider what the capacitor is doing in both cases.
 
Whether the 50 ohm resistance is connected in series with the capacitor or is it the capacitive reactance of the capacitor?
 
rl.bhat said:
Whether the 50 ohm resistance is connected in series with the capacitor or is it the capacitive reactance of the capacitor?

I believe they are in series, as the capacitive reactance depends on the frequency of the source. By giving the resistance as a definitive 50 ohms, it seems to be implied that it does not depend on the frequency of the emf.
 
Back
Top