Rocket Equation and Orbit questions?

AI Thread Summary
The discussion revolves around solving a rocket propulsion problem using the rocket equation and conservation of momentum. A rocket with 80% of its mass as fuel, exhausting it at a velocity of 1500 m/s, ultimately reaches a speed of 2400 m/s after all fuel is expended. Participants clarify that conservation of momentum applies, but the changing mass requires a differential equation approach. The correct formulation involves integrating the relationship between velocity and mass change, leading to the equation v = Vrel * ln(m). Additionally, there is a query about the effects of firing thrusters in orbit, which would indeed alter the orbit to a larger elliptical path with a longer period.
picklepie159
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Homework Statement


#1.) A rocket exhausts fuel with a velocity of 1500 m/s, relative to the rocket. It starts from outer space with fuel comprising 80 per cent of the total mass. When all the fuel has been exhausted the speed is...

(Answer was 2400 m/s)


Homework Equations



Vrel (dm/dt) = m (dv/dt)

(Does conservation of momentum apply here? I know it applied to an earlier problem, but the velocity of the ejected gasses weren't relative to the rocket)

The Attempt at a Solution



1500 (0.8) = 0.2 v
v = 600 m/s

1500 (0.8) = 1 v
v = 1200... still wrong.

Can anyone help me out here??


Also, if a man in a circular orbit around Earth fires his forward thrusters to drop his KE, would he fall into a larger elliptical orbit with a greater period? It was a question in the book I was confused about.
I know K = -E and E = - GMm/2r , or - GMm/2a
 
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picklepie159 said:
Vrel (dm/dt) = m (dv/dt)

(Does conservation of momentum apply here?
Yes, you need to use conservation of momentum, but the mass of the rocket is changing, so you need it in the form of a differential equation. The equation you quoted is fine, but you don't really care about time here. Can you rewrite it without using dt?
 
I understand it's not okay to treat the dt's as a part of a fraction, but I'm learning calc alongside with physics and this is the only thing I could think of. It's not correct, but I would love to learn how to rewrite it as you suggested.

Vrel * dm = m * dv
1500 * 0.8 = dv
 
picklepie159 said:
I understand it's not okay to treat the dt's as a part of a fraction, but I'm learning calc alongside with physics and this is the only thing I could think of. It's not correct, but I would love to learn how to rewrite it as you suggested.

Vrel * dm = m * dv
Yes
1500 * 0.8 = dv
No, dm is a small change in mass. You need to rearrange and integrate the eqn.
 
dv/dm = Vrel/m

v = Vrel * ln(m)

2414 = -1500 * ln(0.2).

Awesome, thanks a lot!
 
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