Rocket Equation and Orbit questions?

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Homework Help Overview

The discussion revolves around a rocket problem involving fuel exhaust velocity and its effect on the rocket's speed, as well as a question about the implications of firing thrusters while in orbit. The subject area includes concepts from dynamics, specifically the rocket equation and orbital mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of conservation of momentum in the context of a changing mass rocket. Questions arise about rewriting equations without time variables and the correct interpretation of mass changes during fuel consumption.

Discussion Status

Some participants have provided guidance on the need to use differential equations due to the changing mass of the rocket. There is an ongoing exploration of how to correctly express the relationship between velocity, mass, and fuel consumption, with various attempts being shared.

Contextual Notes

Participants note the complexity of integrating calculus concepts with physics principles, indicating a learning process that involves grappling with both mathematical and physical interpretations.

picklepie159
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Homework Statement


#1.) A rocket exhausts fuel with a velocity of 1500 m/s, relative to the rocket. It starts from outer space with fuel comprising 80 per cent of the total mass. When all the fuel has been exhausted the speed is...

(Answer was 2400 m/s)


Homework Equations



Vrel (dm/dt) = m (dv/dt)

(Does conservation of momentum apply here? I know it applied to an earlier problem, but the velocity of the ejected gasses weren't relative to the rocket)

The Attempt at a Solution



1500 (0.8) = 0.2 v
v = 600 m/s

1500 (0.8) = 1 v
v = 1200... still wrong.

Can anyone help me out here??


Also, if a man in a circular orbit around Earth fires his forward thrusters to drop his KE, would he fall into a larger elliptical orbit with a greater period? It was a question in the book I was confused about.
I know K = -E and E = - GMm/2r , or - GMm/2a
 
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picklepie159 said:
Vrel (dm/dt) = m (dv/dt)

(Does conservation of momentum apply here?
Yes, you need to use conservation of momentum, but the mass of the rocket is changing, so you need it in the form of a differential equation. The equation you quoted is fine, but you don't really care about time here. Can you rewrite it without using dt?
 
I understand it's not okay to treat the dt's as a part of a fraction, but I'm learning calc alongside with physics and this is the only thing I could think of. It's not correct, but I would love to learn how to rewrite it as you suggested.

Vrel * dm = m * dv
1500 * 0.8 = dv
 
picklepie159 said:
I understand it's not okay to treat the dt's as a part of a fraction, but I'm learning calc alongside with physics and this is the only thing I could think of. It's not correct, but I would love to learn how to rewrite it as you suggested.

Vrel * dm = m * dv
Yes
1500 * 0.8 = dv
No, dm is a small change in mass. You need to rearrange and integrate the eqn.
 
dv/dm = Vrel/m

v = Vrel * ln(m)

2414 = -1500 * ln(0.2).

Awesome, thanks a lot!
 

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