Rocket Momentum: Max Velocity Calculation

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The problem involves a 495 kg rocket initially traveling at 85.0 m/s that fires its engines, imparting an impulse of 15000 Ns over 30 seconds. The calculation for maximum velocity incorrectly treats impulse as a force, leading to the wrong application of the impulse-momentum theorem. The correct approach recognizes that impulse is already a product of force and time, thus not requiring further multiplication by time. The maximum velocity should be calculated by adding the change in momentum directly to the initial momentum. Understanding the distinction between impulse and force is crucial for solving this problem correctly.
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Homework Statement


Far in space, where gravity is negligible, a 495 kg rocket traveling at 85.0 m/s fires its engines. The impulse imparted to the rocket is 15000Ns, for 30 seconds. What is the maximum velocity of the rocket?


Homework Equations


F(delta t)=mv2-mv1


The Attempt at a Solution


v2=((15000*30)+(495*85))/495
v2=994m/s
Why isn't this answer correct?
 
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tani said:

Homework Statement


Far in space, where gravity is negligible, a 495 kg rocket traveling at 85.0 m/s fires its engines. The impulse imparted to the rocket is 15000Ns, for 30 seconds. What is the maximum velocity of the rocket?


Homework Equations


F(delta t)=mv2-mv1


The Attempt at a Solution


v2=((15000*30)+(495*85))/495
v2=994m/s
Why isn't this answer correct?
The impulse is given as 15000 Newton-seconds. you have incorrectly used this value as a force of 15000 Newtons.
 
Force has units of Newtons, not Newton-seconds. The impulse, 15000Ns, is not a force. The time duration has already been factored in.
 
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