Rocket Velocity Determination with Constant Mass Loss and Resistive Force

Click For Summary

Homework Help Overview

The discussion revolves around determining the velocity of a rocket experiencing a linear resistive force while losing mass at a constant rate. The participants are examining the dynamics described by the equation m \dot{v} = -\dot{m}v + f, where the mass loss and resistive forces are key factors in the analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to express the mass as a function of time and clarify the implications of constant mass loss. Questions arise regarding the validity of cancelling differentials and the correct interpretation of variables such as k and m.

Discussion Status

The discussion is ongoing, with some participants clarifying definitions and relationships between variables. There is an indication of progress as one participant believes they have resolved their confusion, but no consensus has been reached on the overall approach or solution.

Contextual Notes

There is a noted confusion regarding the definition of mass as a function of time and the implications of the constant mass loss on the dynamics of the problem. Participants are also exploring the mathematical treatment of the equations involved.

ElderBirk
Messages
6
Reaction score
0

Homework Statement


Consider a rocket is subject to linear resistive force, f = -bv. \dot m is constant. Use the equation: m \dot{v} = -\dot{m }v + f to determine the velocity of the rocket :

since the rate of mass lost is constant
let \dot{m} =k
vex = nuzzle velocity

v = \frac{k}{b} vex (1 - (\frac{m}{m_0})^{\frac{b}{k}})

Homework Equations


Already given above

The Attempt at a Solution


let m= \frac{dm}{dt} \cdot dt = k \cdot dt

k dt \frac{dv}{dt} = -kvex - bv
I don't know if cancelling dt's are allowed but when I solve this equation, it doesn't resemble the expected answer at all.
 
Last edited:
Physics news on Phys.org
You say 'm' is constant... but you have a non-zero m derivative.
Also, m = \int \frac{dm}{dt} dt
 
Make it clear if k is the rate of loss of mass, which means dm/dt=-k or k=dm/dt.
m means the mass of the racket at time t. You need m(t), the expression of mass in terms of time. The original mass is m0. The loss of mass is constant, k. What is m(t), the mass t time after start? It is certainly not kdt as you wrote. ehild
 
Last edited:
I believe I figured it out. Sorry for the confusion. dm/dt =k.

for future reference, if one is looking at this problem, they can easily solve it by raping calculus, i.e.

m dv/dt = m dm/dm dv/dt = m dm/dt dv/dm = m k dv/dm

Now the only dependencies are on m and v, thus by separation of variables the problem becomes solvable.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
7
Views
3K
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 24 ·
Replies
24
Views
3K
Replies
3
Views
2K
Replies
9
Views
3K