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Im a bit confused about where to go with this problem - could anyone possibly help please ?

I have to determine the g forces for the kingda ka rollercoaster

according to research the kingda ka rollercoaster is 139m tall

it shoots up on a 90 degree angle to the right- reaches the peak of the hill then spirals downward on 270 degree angle

according to : http://www.sixflags.com/greatadventure/rides/kingdaka.aspx

I went from here to calc the g force when it drops using the equation (height lost= speed gained) : 1/2mv^2=mgh (independant of mass) so cancel (m's)... -> 1/2v^2=gh -> v^2=2gh -> v=sqrt(2gh)

h=139m

g=10

calc (speed)= 52.73ms^-1

Equation for g force at bottom of loop: (v^2/r)+g/g

*note* i calc the heights of other points and the radius of the ride by making it proportional to the rest of the ride e.g. 139/7.3=x/1.5 -> x= 28.5

anyways , I then calc the g force using equation from above and got a g force of 10!!! this must be wrong or something??? because it should be 4 or less

The only explanation i can think of is maybe friction or banking???? but i dont know how to get the angle for banking - with only the given vertical 270 degree spiral downward- i think the angle is always changing ? could anyone explain SIMPLY please - Im new to this type of physics and any help would be appreciated :)

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# Rollercoasters- find the g forces

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