# Roots of complex equation

## Homework Statement

Find all roots of the equation cos(z)=2 (z is a complex number)

## The Attempt at a Solution

What do they mean find the roots of this equation? We're just going over trig functions and it doesn't say anything about roots so I'm not sure what they're asking for. when I looked on the internet I just kept getting things raised to 1/n. I don't see that all here.

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$$cos x = \frac{e^{ix} + e^{-ix}}{2}$$. Now write z in terms of its reals and imaginarys, z=a + bi. Substitute and get
$$e^{iz} + e^{-iz} = 4$$. Hopefully you can work it from there.