Rotating integrals and circles

lemurs
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kay had a question which i got zero on and now trying to figure out how the hell to do the question.

Given x^2 + (y-1)^2 =1 rotated about the x-axis.

if i could get the solution so i can review it so i can have a better idea how to do it on the mid term.

Hint:, I was told to do with respect to the y-axis.
 
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So how do you set up the integral?
 
well that part of the stuff that confused me.

I set it upas
x = sqrt(1- (y-1)^2)

so my intergral becomes

from 0-2 2(pi) y sqrt(2y - Y^2).

but given that. we end up with a nasty integration... I tryed to get help form soem one but we vouldn't figure it out..
 
That's right. Try the substitution u=y-1. You'll end up with the sum of two integrals, one you can do by another substitution and the other you can do just knowing the area of a circle.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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