Rotation, angular momentum and inertia

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SUMMARY

The discussion focuses on calculating the number of rotations required for a space probe to turn through 30 degrees using an electric motor with a rotor moment of inertia (Im) of 2 x 10^-3 Kg.m² and a probe moment of inertia (Ip) of 12 Kg.m². The correct approach involves applying the conservation of angular momentum, which dictates that the total angular momentum remains constant. The solution confirms that 498 rotations are necessary to achieve the desired orientation of the probe.

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aks_sky
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The rotor of an electric motor has Im= 2 x 10 -3 Kg.m2
about its central axis. The motor is used to change the orientation of a space probe in which it is mounted. If the axis of the motor is mounted parallel to the axis of the probe (Ip= 12 Kg.m^2) calculate the number of rotations required to turn the probe through 30 degrees about its axis.


** I have tried the formula for anuglar momentum and torque here also i have tried to find the ratio between the two bodies but i do not get the correct answer. The answer should be 498 revs but i don't get it right. What else can i try?
 
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aks_sky said:
The rotor of an electric motor has Im= 2 x 10 -3 Kg.m2
about its central axis. The motor is used to change the orientation of a space probe in which it is mounted. If the axis of the motor is mounted parallel to the axis of the probe (Ip= 12 Kg.m^2) calculate the number of rotations required to turn the probe through 30 degrees about its axis.


** I have tried the formula for anuglar momentum and torque here also i have tried to find the ratio between the two bodies but i do not get the correct answer. The answer should be 498 revs but i don't get it right. What else can i try?


Hi aks_sky! :smile:

Just use conservation of angular momentum …

it starts zero, so it stays zero! :wink:

(and remember 30º = 1/12 of a revolution)
 
sweet.. all sorted.. thank u
 

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