Rotation of Disc: Calculating Angular Velocity

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A uniform circular disc with a mass of 10 kg and a radius of 0.2 m experiences a tangential force of 10 N for 10 seconds. The moment of inertia is calculated as I=1/2 mr^2, leading to an angular acceleration of 10 rad/s². Using the rotational kinematics formula, the angular velocity is calculated to be 100 rad/s. However, there is a discrepancy as the provided answer is 10 rad/s, which is deemed incorrect based on the calculations. The discussion concludes that the original calculations appear to be accurate given the parameters provided.
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Homework Statement



A uniform circular disc at rest has mass 10 kg and radius 0.2m. When a force of 10 N is applied tangentially to the disc for 10s, calculate the angular velocity. Given the moment of inertia, I=1/2 mr^2

Homework Equations





The Attempt at a Solution



Using rF=I(alpha) , alpha = 10 rad/s^2 after substituting r=0.2 , m=10 , F=10

Then, using the rotational formulas,

w = w0 + at (w is meant to be omega)

w = 0+ (10)(10) = 100 rad /s

but the answer given is 10 rad/s .
 
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Your answer is correct. Unless you've copied the given information incorrectly, the answer given is wrong.
 
chaoseverlasting said:
Your answer is correct. Unless you've copied the given information incorrectly, the answer given is wrong.

This is the working of the answer.

Iw=rt

where I, the moment of inertia, w=angular velocity, r= the radius, and t the time.

and from here, the angular velocity is evaluated. I haven't seen that formula before.
 
Yeah, your answer is right given that the info is correct

\omega=\frac{2F}{mr}t
 
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