Rotation of Rigid Bodies- mastering physics 9.72

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The discussion focuses on calculating the linear speed of a saw blade and its radial acceleration. The motor operates at 3450 revolutions per minute, which converts to 361.283 radians per second. To find the tangential speed, the radius of the saw blade, derived from its diameter of 0.208 m, is used in the formula v = rw. The second pulley, being half the diameter of the motor pulley, rotates at double the speed of the motor, confirming the relationship between the two shafts. Understanding these calculations helps explain why sawdust does not adhere to the blade's teeth due to the radial acceleration.
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The motor of a table saw is rotating at 3450 rev/min. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208 m is mounted on the same rotating shaft as the second pulley.
PART A: The operator is careless and the blade catches and throws back a small piece of wood. This piece of wood moves with linear speed equal to the tangential speed of the rim of the blade. What is this speed?
PART B:Calculate the radial acceleration of points on the outer edge of the blade to see why sawdust doesn't stick to its teeth.

I converted 3450 rpm to 361.283 rads/s. I know that v=rw, but how do I calculate this without the radius being given?
 
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Well they gave you the diameter of the saw blade, so you can divide that by two to get its radius. There's an additional step though, you need to take account of the fact that the shaft which is driving the blade is rotating at a different rate than the shaft which is connected to the motor.
 
Is the second shaft rotating twice as fast since its on a belt half the diameter of the first?
 
Got It. Thanks.
 
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