Rotational Motion (Inclined Plane)

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A solid cylinder and a solid sphere on an inclined plane will reach the ground at different times due to their mass distribution. The sphere, with a lower moment of inertia (2/5mr^2), will roll down faster than the cylinder (1/2mr^2). To mathematically demonstrate this, one can use energy conservation principles, calculating the kinetic energy at the bottom of the incline. The object with greater velocity upon reaching the bottom will be the one that arrives first. Understanding these concepts is crucial for success in physics assessments.
Izzybee
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[SOLVED] Rotational Motion (Inclined Plane)

Hi Everyone!
My question is: A solid cylinder and a solid sphere are resting on top of a inclined plane. Using mathematics, which object would reach the ground first. Given: I (cylinder) = 1/2mr ^2 and I (sphere) = 2/5 mr ^2.

I know that the sphere would reach the ground first because of its mass distribution, but I am not quite sure how to show it mathematically. My teacher said a problem like this will show up on my test Monday!

Please help!
 
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What is the energy of a rotating solid?
 
I think what kurdt's suggesting is to try using energy methods.

p.s. Are you taking AP Physics C?
 
CALCULATE THE KINETIC ENERGY OF THE CYLINDER AND THE SPHERE AT THE BOTTOM OF THE PLANE...AND THEN FIND WHICH OF THE TWO HAS THE GREATER VELOCITY...

THE ONE WITH GREATER VELOCITY IS THE ONE WHICH COMES DOWN EARLY..

USE THE FORMULA..

mgh=1/2mv^2(1+k^2/r^2)

K(RADIUS OF GYRATION)==I/M
 
Thanks, but I figured it out!
P.S: What is AP Physics C??
 
Advanced Placement college board course. Its an American thing I believe.
 
No I am not.
 
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