Rotational Motion of a car on a curve

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Homework Help Overview

The discussion revolves around a physics problem involving the rotational motion of a car navigating a banked curve. The scenario includes a car's mass, speed, and the radius of the curve, with a focus on determining the banking angle required for the car to maintain its path without friction.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the reasoning behind dividing one equation by another to isolate the banking angle. There is a discussion on the algebraic manipulation of equations and the implications of choosing division over multiplication in this context.

Discussion Status

The conversation is active, with participants questioning the algebraic steps taken to derive the banking angle. Some have provided insights into the reasoning behind their choices, while others express uncertainty about the manipulation of the equations.

Contextual Notes

Participants are navigating the constraints of the problem, including the requirement for the car to maintain its path without friction and the specific equations provided for analysis.

ajmCane22
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Homework Statement



A 600 kg car is going around a banked curve with a radius of 110m at a speed of 24.5 m/s. What is the appropriate banking angle so that the car stays on its path without the assistance of friction?

Homework Equations



N cos{theta} = mg
N sin{theta} = mv^2/r

The Attempt at a Solution



I was told to divide the second equation by the first equation which gives tan{theta} = v^2/rg
I used this equation and got the right answer, but I'm just wondering if somebody could please explain WHY the second equation was divided by the first and not the other way around.
 
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ajmCane22 said:
I was told to divide the second equation by the first equation which gives tan{theta} = v^2/rg
I used this equation and got the right answer, but I'm just wondering if somebody could please explain WHY the second equation was divided by the first and not the other way around.

If you divided the first equation by the second, you would get:

cot(θ) = (gr/v2)

θ = arccot(gr/v2).

I imagine that ought to give you the right answer as well...
 
This might be a really dumb question, but why do you divide instead of multiply?
 
ajmCane22 said:
This might be a really dumb question, but why do you divide instead of multiply?

You do whatever algebraic manipulation makes it easiest to solve for theta. With N's on both lefthand sides, and m's on both righthand sides, it seems natural to get rid of both of them by dividing them out. Then you're left with something that is only in terms of theta on the lefthand side.
 

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