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## Homework Statement

A 30 cm ruler has a mass of 5g. Mark the pivot point and calculate the torque for the following situation:

Ruler extends 10cm out from desk

## Homework Equations

T= r x F

F= |F|sinΘ

F= m Fg

## The Attempt at a Solution

F= mFg

= (0.005kg) (9.8 m/s^2)

=0.049 N

T= r x F

=|r||F|sinΘ

=(0.10m)(0.049N) sin 90 degrees

=0.00049 Nm

The only thing Im not sure on is that only a third of the ruler is hanging off the desk so I am not sure if I have divide the mass.