1. The problem statement, all variables and given/known data A 30 cm ruler has a mass of 5g. Mark the pivot point and calculate the torque for the following situation: Ruler extends 10cm out from desk 2. Relevant equations T= r x F F= |F|sinΘ F= m Fg 3. The attempt at a solution F= mFg = (0.005kg) (9.8 m/s^2) =0.049 N T= r x F =|r||F|sinΘ =(0.10m)(0.049N) sin 90 degrees =0.00049 Nm The only thing Im not sure on is that only a third of the ruler is hanging off the desk so I am not sure if I have divide the mass.