I've been trying this question for quite some time and have given up.(adsbygoogle = window.adsbygoogle || []).push({});

Prove that a mass,M , suspended from a fixed point by a helical spring, which obeys hooke's law, undergoes simple harmonic motion when it is displaced vertically from its equilibrium position.

Say I displace the mass spring upwards, e metres. Then I can say:

Mg + ke = Ma ?

When the mass is at far bottom then

kx - Mg = -Ma ?

When I equate these two I get kx=-ke, which proves nothing. :yuck:

Thanks

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# S.H.M for mass spring system

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